I want to get a list of all the keys in the secondary dictionaries, take out duplicates and return as a list.
So let's say we have something like this:
d1 = { 1 : "aaa", 2 : "bbb" } d2 = { 22 : "yyy", 33 : 'zzzzz' } d3 = { 141 : 'xyz', 123 : 'abc', 231 : 'lmnop' } myd2d = { 'a' : d1, 'b' : d3, 'c' : d2 }The desired answer is
[1,2,22,33,141,123,231]Not necessarily in that order. The straightforward way to do it would be:
result = [] for k,v in myd2d.iteritems(): for mykey in v.keys(): result.append( mykey )I suppose the other way might be more pythonic:
r = sum( (v.keys() for k,v in myd2d.iteritems()), [] )
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